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Published: 2010-03-13 14:23:37 +0000 UTC; Views: 2201; Favourites: 30; Downloads: 63
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Description
I felt it was about time i launched a new emoticon shading contest, so here it is
Once you have guessed as many as you can, you need to send the names in a note to my `Synfull account. The quickest 3-5 people to get all 15 right (or the most right in a week) will win a feature from me and anyone else who wishes to provide features.
You can enter as many times as you wish, but please send all 15 names within one single note. (ie all 15 in one, not one name per note). please don't leave guesses in the comments. Its spoils the fun. If you get any wrong iβll let you know and you can guess again until the game is over. If itβs been a few days and people are struggling then i may release some hints
So if you think this sounds fun, get going
Please note: These basepacks were all obtained with the owner's permission. They each are owned by the original artist and therefore not free for use based purely on this deviation.
Prizes
10 points donated by `krissi001
Feature from `Synfull
Feature from `arrioch
Feature from =BlueSnowGiesha
Feature from `krissi001
Winners
1. =Sinister-Starfeesh (in 3 hours 54min )
2. `krissi001
3. =BurgerBunny
4. =stuck-in-suburbia
5. ~kittyangel95
Hints
To make it simpler (since all wanting to do the hard version seem to have given up) below is a list of 25 emoticonists. Of the 25, 15 own the shadings abover and 10 are not included. You still need to tell me who owns which one, but you now have a reduced number to look through. th prizes are also updated
(In alphabetical order)
`arrioch
=BlissfullySarcastic
`brokenboulevard
`capncraka
`CookiemagiK
`Droneguard
^elicoronel16
~flashfrog
^Hanratty-Stock
=KimRaiFan
`krissi001
=ManiacalMuffin
=MenInASuitcase
^mintyy
=MixedMilkChOcOlate
=Mr-Jaunty
*nillemotes
=Oktanas
=renekotte
=SparklyDest
=steph1254
*stevanov
=stuck-in-suburbia
`Synfull
~Wooded-Wolf
Related content
Comments: 77
Synfull In reply to ??? [2010-03-23 01:22:50 +0000 UTC]
I noted all the owners in advance so if you had no note its definately not yours
π: 0 β©: 0
arrioch [2010-03-22 23:53:19 +0000 UTC]
Congrats to all, they're getting feature in my next journal.
π: 0 β©: 1
Krissi001 [2010-03-22 17:19:38 +0000 UTC]
YaaY
I will give them the points now
and i will feature them as soon as i write a new Journal
π: 0 β©: 2
Synfull In reply to CookiemagiK [2010-03-20 21:40:47 +0000 UTC]
still chance to enter. tis not over yet
π: 0 β©: 0
Synfull In reply to H34 [2010-03-20 01:20:43 +0000 UTC]
Since only 2 people entered without them i might as well make it 'very easy' if thats what it takes to make people enter
π: 0 β©: 0
TimberClipse [2010-03-17 21:47:52 +0000 UTC]
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
Someone
I WIN!!!!!
lol, I have not the slightest clue.
TC
π: 0 β©: 1
Krissi001 [2010-03-17 17:28:54 +0000 UTC]
I can offer 10 points for the 5 winners and a journal feature of course
π: 0 β©: 1
BlueSnowGiesha [2010-03-16 22:21:04 +0000 UTC]
if it's okay, i'll put out features for the winners when it's all over. c:
π: 0 β©: 1
Synfull In reply to BlueSnowGiesha [2010-03-17 10:22:23 +0000 UTC]
thanks for the offer
π: 0 β©: 1
BlueSnowGiesha In reply to Synfull [2010-03-18 00:57:43 +0000 UTC]
no problem. [:
will you be accepting it?
π: 0 β©: 1
Synfull In reply to BlueSnowGiesha [2010-03-19 17:01:12 +0000 UTC]
added it to the prize list
π: 0 β©: 1
FoxClaw100 In reply to Synfull [2010-03-16 00:50:30 +0000 UTC]
but ... I'm sure one of them is yours >3> ... *stares*
π: 0 β©: 0
BurgerBunny In reply to jennifuh [2010-03-22 19:33:28 +0000 UTC]
I totally misinterpreted that.
π: 0 β©: 0
xXbBGurlx [2010-03-14 00:45:40 +0000 UTC]
so do u have to search through the group and see who made each one of the emoticon base ?
π: 0 β©: 1
xXbBGurlx In reply to Synfull [2010-03-15 08:51:05 +0000 UTC]
can i ask which group am i suppose to look through cause i cant find it
π: 0 β©: 1
Synfull In reply to xXbBGurlx [2010-03-15 08:59:11 +0000 UTC]
Just emoticonists in general
π: 0 β©: 1
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