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# Statistics
Favourites: 373; Deviations: 66; Watchers: 91
Watching: 64; Pageviews: 18526; Comments Made: 197; Friends: 64
# Comments
Comments: 33
Robyn-Jane In reply to jackcornelius [2014-11-28 23:24:56 +0000 UTC]
Why Thankyouuu !Β
π: 0 β©: 0
Pokemonever [2013-05-06 15:51:47 +0000 UTC]
Hi Robyn-Jane
Here is the result of my Work:
[link]
I hope you like, what i have make with your graphic!
π: 0 β©: 1
Robyn-Jane In reply to Pokemonever [2013-05-06 23:47:31 +0000 UTC]
Thankyou, I love it !
π: 0 β©: 0
LetTheBloodRunRed [2012-07-04 23:06:54 +0000 UTC]
Thanks for the fav! You have a wonderful gallery!
π: 0 β©: 1
Robyn-Jane In reply to LetTheBloodRunRed [2012-07-06 11:03:38 +0000 UTC]
No Problem I like your work too
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Robyn-Jane In reply to joeyglockner [2012-04-16 12:12:31 +0000 UTC]
Thank you! Means alot
π: 0 β©: 0
enigmista91 [2012-03-14 21:27:07 +0000 UTC]
Sorry for disturbing, I'm participating in a very important competition for me and to win and I need likes on this youtube video.
Could you give me a hand and like this video?
[link]
thanks!!!
π: 0 β©: 0
RoOnyM [2011-11-09 23:53:25 +0000 UTC]
much Respect
** Twitter >>> [link]
My Video >>> [link]
π: 0 β©: 0
Nataly1st [2011-02-07 16:49:17 +0000 UTC]
My dear , I am very appreciate your support!!
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LaraVilya [2011-01-26 19:42:06 +0000 UTC]
Hello! If you have some art concerning vampires, maybe you'd like to join my new group! [link] (it's really new, but it will evolve ) If you don't want to share your art for now, you can just be a member or watch us.
Thanks for reading, and have a nice day
π: 0 β©: 1
Robyn-Jane In reply to LaraVilya [2011-01-27 20:24:22 +0000 UTC]
Awesome i'd love to!
But the link doesn't work
π: 0 β©: 1
LaraVilya In reply to Robyn-Jane [2011-01-27 20:27:11 +0000 UTC]
Oh I'm sorry [link] This should work now!
π: 0 β©: 0
MKCVXIII [2011-01-23 20:37:13 +0000 UTC]
Good artwork and great talent! Love your pics, hereΒ΄s a llama and watch for you.
π: 0 β©: 1
Dv900 In reply to Robyn-Jane [2011-01-23 19:57:30 +0000 UTC]
You're very welcoke!
Can i help you if you need help about DA?
π: 0 β©: 1
Robyn-Jane In reply to Dv900 [2011-01-23 20:39:04 +0000 UTC]
That would be most helpful, thanks for the offer ^^
π: 0 β©: 1