HOME | DD

Published: 2013-03-23 13:26:37 +0000 UTC; Views: 1980; Favourites: 26; Downloads: 2
Redirect to original
Description
Sorry I haven't been uploading stuff for a while. Stuff's been busy at school, mostly rehersing for "The Producers". But now I'm on Spring Break & I have a bit of stuff I'd like to upload. Here's one of them: a dramatic drawing of "The Muppets... Again!" lead villain, Constantine. He's apparently the world's #1 criminal doppelgΓ€nger of Kermit. The only difference is he has a mole on his cheek. I think this is the best dark shadowy shading I've done. I tried to get a scary Hannibal Lecter feel to this.Comment & enjoy!
Constantine (c) Jim Henson Company
Related content
Comments: 13
AverageJoeArtwork In reply to Constantinebad-frog [2014-08-13 20:05:08 +0000 UTC]
That was just added 'cause you know how most cartoon moles have small hairs coming out? So...
π: 0 β©: 1
Constantinebad-frog In reply to AverageJoeArtwork [2014-08-13 21:58:40 +0000 UTC]
Ahh. Β But all een all, I love how you drew me.
π: 0 β©: 1
AverageJoeArtwork In reply to Constantinebad-frog [2014-08-14 00:58:02 +0000 UTC]
Great to know.
π: 0 β©: 1
Constantinebad-frog In reply to AverageJoeArtwork [2014-08-14 02:34:59 +0000 UTC]
I was geeving you compliment.
π: 0 β©: 1
AverageJoeArtwork In reply to Constantinebad-frog [2014-08-14 02:45:29 +0000 UTC]
I'm aware.
π: 0 β©: 1
AverageJoeArtwork In reply to Constantinebad-frog [2014-08-20 18:07:40 +0000 UTC]
& you should just wait for what I'm gonna do this October with you.
π: 0 β©: 1
Constantinebad-frog In reply to AverageJoeArtwork [2014-08-20 23:16:41 +0000 UTC]
Oh good.....that's great!
π: 0 β©: 0
KessieLou [2014-03-02 22:53:54 +0000 UTC]
*tries not to pull an Austin Powers when looking at Constantine's mole* Mole...! Mole...!>~<
π: 0 β©: 0
Lizlovestoons12 [2014-01-21 00:13:22 +0000 UTC]
I can't wait to see "Muppets: Most Wanted", myself!
π: 0 β©: 0
innerchild96 [2013-03-25 23:12:50 +0000 UTC]
Ooh, he looks so mysterious! I can't wait for "The Muppets...Again".
π: 0 β©: 1
AverageJoeArtwork In reply to innerchild96 [2013-03-26 02:08:53 +0000 UTC]
That's what I was going for.
π: 0 β©: 0