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colorfultrick — Midas11
Published: 2018-11-09 15:59:57 +0000 UTC; Views: 14268; Favourites: 123; Downloads: 172
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Doesn't work that way on the integers. . .
. . .just sayin'.
*leaves*
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Doesn't it? I thought with the limit on 0+ it'd work
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No. Its indeterminate. Infinity isn't a number, but rather the concept of arbitrary largeness. Similarly, the idea of a limit is the ability to get arbitrarily close to something. a/0 is never going to be defined, and the closest you can get to it is a/1. The largest you can make a/n is a.
Of course, none of that matters. After all, they created "Artificial Stupidity" right?
Oh, and all the 0+ means is that the limit is being approached from the right. Which does matter if you are working on the reals. For example a/x as x tends to zero from the LEFT is negative infinity, but positive from the right. Assuming a> 0 of course.
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Right.....but 0+ and not simply 0 was specified. The robot doesn't leave the creators half transformed, or 78% transformed, but goes to 100%. It's trying for infinite wealth.
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It doesn't matter if its from the left or the right. On the integers, that limit does not exist. On the reals, the way the limit is approached matters, as it determine the sign on infinity.
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