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Published: 2012-01-02 11:48:15 +0000 UTC; Views: 6485; Favourites: 195; Downloads: 256
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Description
Model: Emily KwongMUA: Mary Li
Hair: Me!
Photography: Me
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Comments: 14
lftaddeo [2012-01-09 15:56:53 +0000 UTC]
Hi there! I'm a drawing student, and used that picture in my sketchbook, while practicing... the result is in [link] and i would like you to see it!
If you wish, i'll remove the deviation from my galery!!!
But i hope that you and the model like it enough to allow me to keep it
π: 0 β©: 1
Eman333 In reply to lftaddeo [2012-04-09 11:13:43 +0000 UTC]
Love it, great work. Sorry for the late reply
π: 0 β©: 0
lftaddeo [2012-01-09 15:53:53 +0000 UTC]
Hi there! I'm a drawing student, and used that picture in my sketchbook, while practicing... the result is in [link] and i would like you to see it!
If you wish, i'll remove the deviation from my galery!!!
But i hope that you and the model like it enough to allow me to keep it
π: 0 β©: 0
Tataouin [2012-01-04 18:18:06 +0000 UTC]
I really like this look; like a modern look taken from ancient Chinese paintings! I love it! It's stunning, beautiful, mysterious, dangerous, and elegant, all at once!! Beautiful work!
π: 0 β©: 0
aktell [2012-01-02 18:58:07 +0000 UTC]
(Twitter Tweet) β Was send on @aktell2007 and @UpperCutArtists - Check out Em by *Eman333 on @deviantART [link]
π: 0 β©: 0
multicoloredpenguins [2012-01-02 15:52:36 +0000 UTC]
The makeup is great! And her expression is awesome too!!!
π: 0 β©: 0
GeraldII [2012-01-02 12:58:26 +0000 UTC]
Another amazing shot for your portfolio, love how this gives off a really nice warm feeling, yet she gives a very strong presences. I think it is cool youβre getting into the hair styling, does this mean I can come to you for tips in that as well now
π: 0 β©: 1
Eman333 In reply to GeraldII [2012-01-02 13:00:54 +0000 UTC]
Haha thanks Gerald... But I'd ask for hair styling advice from someone else
π: 0 β©: 1
GeraldII In reply to Eman333 [2012-01-02 13:03:57 +0000 UTC]
Haha oh if you insist my friend, I suppose I will search elsewhere.
π: 0 β©: 0