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ImaginDevan β Who could this be? (Guess in the comments?)
#hermit #imagin #lemur #magic #magician #monkey #powerful #ref #reference #sage #sennin #shaman #strong #zaboo #zoboomafoo
Published: 2015-11-20 13:00:02 +0000 UTC; Views: 1135; Favourites: 7; Downloads: 2
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Who could this be...? This Sennin that I see... Who could he be...?Can any of you guess? (Besides Sybil, who has seen him, before.)
He is actually an important figure from my childhood, reimagined as an... Imagin. Haha!
Also, he seems to be a very powerful imagin. You see... Ah, how do I explain? When I RP on DeviantArt, me and the other imagin can easily communicate with other people. This is because the comments system is not instantaneous. However, Loki seems to have troubles talking on Skype, as though he cannot synchronize with it. That is not the case for this Sennin, who can easily talk anywhere that he wants.
???: Of course I can talk where I want! Why wouldn't I be able to? Zahahahahaha!
It's actually very good that he came along! I was attacked by a demon, recently, and this Lemur here managed to save me. He told me that this demon is feeding off of a very specific type of despair, and that he is the perfect cure.
Note: I don't know how to translate Sennin (δ»δΊΊ) into English. In Japanese, it is like a powerful and mysterious person who lives in the mountains. An example is the Sennin from Kamen Rider Ghost.
Ah, wait a minute! That branch! The fruit on it! Can it be?! 0_0
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Comments: 62
Okayβ¦so what do you want to talk about?
π: 0 β©: 1
Zaboo: Well, I was wondering. You are my contract holder, yes? That means you are like Sanzo?
(Ah, this is difficult to explain. 
π: 0 β©: 1
(Really?)
Me: I'm not sureβ¦
π: 0 β©: 1
(I think that... Zaboo wants to be more like the king, right? So, he wants to find people around him who are similar to characters from the story.
π: 0 β©: 1
(Oh I see. So what can I do?)
π: 0 β©: 1
(Well... Uh... Zaboo thinks that you are like the one who the king follows. Then, Holly would be the pig... And, he is looking for a Kappa, too. I'm not sure if this would really do anything, though.
π: 0 β©: 1