HOME | DD

kingofthedededes73 — defeated by a dancing squirtle

Published: 2014-08-14 19:38:50 +0000 UTC; Views: 576; Favourites: 17; Downloads: 5
Redirect to original
Description based off the latest japan episode of pokemon xy, Tierno's squirtle dances like tierno does, and even more typical of the pokemon anime logic, a tiny basic pokemon beats a fully evolved pokemon. so a dancing squirtle defeats a full grown conkeldurr? well the only way this could make some logical sense is if the squirtle is like level 15 and the lowest level you can have a conkeldurr is 25, and there are times where lower level pokes can defeat higher ones. and apparently this squirtle can, and dance like michigan j frog while doing so www.youtube.com/watch?v=YkfU1J…

lol so anyways comment and enjoy
pokemon belongs to nintendo
Related content
Comments: 8

TyrannosaurusRex-123 [2014-09-27 11:19:45 +0000 UTC]

Was that Capoeira in the picture?

šŸ‘: 0 ā©: 1

kingofthedededes73 In reply to TyrannosaurusRex-123 [2014-09-27 13:49:47 +0000 UTC]

i don't know what you're talking about

šŸ‘: 0 ā©: 0

ask-waluigi-time [2014-08-18 08:08:33 +0000 UTC]

Little turtle bastard....I'd love to see Conkeldurr win a battle for once!

šŸ‘: 0 ā©: 1

kingofthedededes73 In reply to ask-waluigi-time [2014-08-18 13:12:37 +0000 UTC]

yea too bad it hasn't happened yet

šŸ‘: 0 ā©: 0

PikaNepGamer [2014-08-15 19:03:50 +0000 UTC]

lol. Imagine Squirtle getting a lot of experince points for defeating a high leveled Pokemon. XD

šŸ‘: 0 ā©: 1

kingofthedededes73 In reply to PikaNepGamer [2014-08-15 20:08:27 +0000 UTC]

probly a good amount, unless that conkeldurr was like level 25, but still if squirtle was lower he'd probly get a lot

šŸ‘: 0 ā©: 1

PikaNepGamer In reply to kingofthedededes73 [2014-08-15 20:09:05 +0000 UTC]

and probably Squirtle might evolve after the battle is over. XD

šŸ‘: 0 ā©: 1

kingofthedededes73 In reply to PikaNepGamer [2014-08-15 20:10:17 +0000 UTC]

since it was on the anime that this happened, nope it was still a squirtle.

šŸ‘: 0 ā©: 0