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Published: 2012-06-18 17:16:25 +0000 UTC; Views: 16399; Favourites: 212; Downloads: 200
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Description
Pan ssj version de toybleLineart y color : Por mi
Trabajo : Sai y PSD
Doujin: DBAF(Toyble)
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Pan ssj version toyble
Lineart and color: By me
Job: Sai and PSD
Doujin: DBAF(Toyble)
Dragon Ball Β©Akira Toriyama
Related content
Comments: 30
Fatefulbrawl [2018-04-28 17:37:05 +0000 UTC]
This should have happened in cannon!
Glad you made the fix on that mistake though
π: 0 β©: 1
Fatefulbrawl In reply to Metamine10 [2018-04-28 23:18:18 +0000 UTC]
Hey, do you have any Saiyan OCs?
π: 0 β©: 1
Metamine10 In reply to Fatefulbrawl [2018-04-29 20:34:57 +0000 UTC]
Yamira, one of my characters, is practically half sayan and terricola.
π: 0 β©: 1
Fatefulbrawl In reply to Metamine10 [2018-04-30 01:32:01 +0000 UTC]
May I see her?
Also what's a terricola?
π: 0 β©: 1
Metamine10 In reply to Fatefulbrawl [2018-04-30 23:00:55 +0000 UTC]
the normal race, common person.
π: 0 β©: 1
Metamine10 In reply to Fatefulbrawl [2018-05-01 23:12:57 +0000 UTC]
Yes, well, thank you, see you.
π: 0 β©: 1
Fatefulbrawl In reply to Metamine10 [2018-05-02 00:55:34 +0000 UTC]
What about the Oc you mentioned?
π: 0 β©: 0
BH-Ouji [2016-08-24 19:25:03 +0000 UTC]
I was looking for Pan SSJ1 arts and found this, have a fave
π: 0 β©: 1
hulkboyjr [2016-08-04 01:32:35 +0000 UTC]
It will be a day for all DBZ fans to remember if Pan actually ever goes Super Sayian... But honestly, I don't like how her hair is spiked up. I know that happens with Super Sayians, but spikey hair looks bad on her. It looks better smooth and flat.
π: 0 β©: 1
Metamine10 In reply to hulkboyjr [2016-08-04 01:50:48 +0000 UTC]
In my opinion, it looks great.Β Β
π: 0 β©: 0
rgshakira [2014-05-01 21:04:31 +0000 UTC]
Si Goten y Trunks heredaron el super saiyan, por quΓ© Pan no?Β Β Β Β Β Β Β Β Β
π: 0 β©: 2
Metamine10 In reply to rgshakira [2014-05-01 21:06:41 +0000 UTC]
Si pues es por lΓ³gica, gracias por comentar.Β Β Β
π: 0 β©: 0
el-maky-z [2012-06-19 11:50:26 +0000 UTC]
Muy bueno!
Ojala hubiera aparecido asΓ en la serie
π: 0 β©: 0