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nekonoodle-kohai β€” Error's red string of fate

#au #error #redstring #sans #undertale #errorsans #error_sans_errortale
Published: 2016-06-12 15:38:52 +0000 UTC; Views: 621; Favourites: 37; Downloads: 0
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Description The red string connects two people who are destined for each other, regardless of anything. The red string will connect two people forever, despite any circumstance. The thread may stretch or tangle, but will never break.

Who do you think should be at the other end of Error's string? Maybe I will draw the other end...

Error!Sans is owned by Crayon Queen.
Undertale is owned by Toby Fox.
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Comments: 10

AweCraftBlox [2016-06-13 18:34:44 +0000 UTC]

Error Papyrus?

πŸ‘: 0 ⏩: 1

nekonoodle-kohai In reply to AweCraftBlox [2016-06-14 06:37:15 +0000 UTC]

That works! Tell me your thoughts on inkSans...

πŸ‘: 0 ⏩: 1

AweCraftBlox In reply to nekonoodle-kohai [2016-06-14 09:19:15 +0000 UTC]

Hmmmm... They're both pretty good. Sans doesn't even really know Error!Papyrus, yet, so I guess inkSans might be a better choice... But then there's the fact that Error's red string connects someone who he's tied together with fate. So They would both make sense, but you're the creator, so you choose his fate, really. I'm not good at making decisions, sooooo...Β 

πŸ‘: 0 ⏩: 1

nekonoodle-kohai In reply to AweCraftBlox [2016-06-14 18:45:09 +0000 UTC]

Thanks~ much appreciated. I suppose you'll have to see....

πŸ‘: 0 ⏩: 1

AweCraftBlox In reply to nekonoodle-kohai [2016-06-15 01:11:08 +0000 UTC]

M'kay! ^-^ I'll just be waiting... And waiting... For the instant noodles to be ready.

πŸ‘: 0 ⏩: 0

CKFlame [2016-06-12 21:01:26 +0000 UTC]

This is AWESOME

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nekonoodle-kohai In reply to CKFlame [2016-06-12 21:39:04 +0000 UTC]

Aww, thank you!!

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ILoveMyCat456 [2016-06-12 17:24:33 +0000 UTC]

This is really amazingΒ Β 

πŸ‘: 0 ⏩: 1

nekonoodle-kohai In reply to ILoveMyCat456 [2016-06-12 18:19:46 +0000 UTC]

Thank you~~~!!

πŸ‘: 0 ⏩: 1

ILoveMyCat456 In reply to nekonoodle-kohai [2016-06-12 18:34:20 +0000 UTC]

You're welcomeΒ Β 

πŸ‘: 0 ⏩: 0