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Published: 2015-03-22 21:46:21 +0000 UTC; Views: 2001; Favourites: 32; Downloads: 6
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Description
This was based on a Vine that I found on the internet the other day, it really made me laugh that I said to myself "This needs to get ponified"! That's what I did. :3MLP;FiM (c) Hasbro
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Comments: 56
Ismalith [2015-03-24 22:52:49 +0000 UTC]
Why did you use two variables?
1122x²+4257yx+2x-4y
-----------------------------
x² +393xy + 390y²
Is as far as I can go here, fore more there is only plotting in math programs as far as my abilities go.
👍: 0 ⏩: 0
tigreanpony [2015-03-23 20:57:31 +0000 UTC]
Lol, that was hilarious. but in the second that question still stands true. Truth be told that type of math is more for technical work and scientific work but still is funny.
👍: 0 ⏩: 1
sweetymimy22 [2015-03-23 17:20:02 +0000 UTC]
hahaha no really why should we know that ....?? Such computing tasks take more than the scientists
👍: 0 ⏩: 1
Deviantaphant [2015-03-23 03:42:53 +0000 UTC]
The furthest I could get was 2x(561x+1)+y(4257-4)
___________________
(390y^2)+3xy+x
Is that good enough, Twilight?
👍: 0 ⏩: 1
PaulySentry In reply to Deviantaphant [2015-03-23 06:38:14 +0000 UTC]
Wow! Did you resolve it? That's amazing!
👍: 0 ⏩: 1
Azzzanadra In reply to PaulySentry [2015-03-23 19:31:44 +0000 UTC]
no, he needs to find the value of x and y.
i don't think that's how you do it either.
👍: 0 ⏩: 1
PaulySentry In reply to Azzzanadra [2015-03-23 21:13:15 +0000 UTC]
I suck at algebra. So, I technically don't know what did he do.
👍: 0 ⏩: 2
Deviantaphant In reply to PaulySentry [2015-04-11 15:06:27 +0000 UTC]
I couldn't find a way to simplify it any further, you are literally going to have to plot it on a graph from there. I don't have the time for that.
👍: 0 ⏩: 0
PaulySentry In reply to Extraxi [2015-03-23 06:35:45 +0000 UTC]
Hehe, have you watched it? It's pretty good. Thanks!
👍: 0 ⏩: 1
Extraxi In reply to PaulySentry [2015-03-23 22:20:40 +0000 UTC]
I have seen a version of it, I don't know if it's the original.
👍: 0 ⏩: 0
TheAdorableOshawott [2015-03-22 23:38:08 +0000 UTC]
Y apenas estoy viendo el método de factorización. :v
👍: 0 ⏩: 1
PaulySentry In reply to TheAdorableOshawott [2015-03-22 23:50:30 +0000 UTC]
Yo estoy viendo Trigonometría.
👍: 0 ⏩: 1
TheAdorableOshawott In reply to PaulySentry [2015-03-23 00:26:58 +0000 UTC]
Eso ya lo vi el año pasado, no está tan difícil si pones atención. :v
👍: 0 ⏩: 1
PaulySentry In reply to TheAdorableOshawott [2015-03-23 06:36:51 +0000 UTC]
Sí, no está nada difícil. Es fácil.
👍: 0 ⏩: 1
TheAdorableOshawott In reply to PaulySentry [2015-03-23 07:28:23 +0000 UTC]
Seh, es muy fácil. :v
👍: 0 ⏩: 0
Fee-F33 [2015-03-22 23:31:19 +0000 UTC]
I say that all the time
for new problems, then I see why ^^'
👍: 0 ⏩: 1
PaulySentry In reply to Fee-F33 [2015-03-22 23:34:40 +0000 UTC]
XD Yeah, you'll never know when something like this could happen.
👍: 0 ⏩: 0
PaulySentry In reply to Hero-Mode [2015-03-22 22:24:01 +0000 UTC]
I don't suck at math, I just don't like it.
👍: 0 ⏩: 1
Count-Author In reply to PaulySentry [2015-03-22 22:22:09 +0000 UTC]
Eeyup! Too bad you flunked that math course!
👍: 0 ⏩: 1
Count-Author In reply to PaulySentry [2015-03-22 22:41:43 +0000 UTC]
Eh, it's okay. I did too.
👍: 0 ⏩: 0
liamwhite1 [2015-03-22 21:54:15 +0000 UTC]
Solve for x:
x(x - 2 + m²x + 2mb + 2mk) = r² - b² - h² + 2bk
Have fun.
(PROTIP: don't try, moron)
👍: 0 ⏩: 2
Crad-Rin-Vah In reply to liamwhite1 [2015-03-22 22:02:55 +0000 UTC]
but... but there are 3 X's DX
👍: 0 ⏩: 1
liamwhite1 In reply to Crad-Rin-Vah [2015-03-22 22:31:35 +0000 UTC]
x(x - 2 + m²x + 2mb + 2mk) = r² - b² - h² + 2bk
rewrite as quadratic
x(x + m²x + 2mb + 2mk) - 2x = r² - b² - h² + 2bk
x²(1 + m²) + x(2mb + 2mk - 2) = r² - b² - h² + 2bk
complete the square
x² + x(2mb + 2mk - 2)/(1 + m²) = (r² - b² - h² + 2bk) / (1 + m²)
x² + x(2mb + 2mk - 2)/(1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)² = (r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
(x + (2mb + 2mk - 2)/(2 + 2m²))² = (r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
isolate
x + (2mb + 2mk - 2)/(2 + 2m²) = ± √(r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²
x = - (2mb + 2mk - 2)/(2 + 2m²) ± √((r² - b² - h² + 2bk) / (1 + m²) + (2mb + 2mk - 2)²/(2 + 2m²)²)
👍: 0 ⏩: 2
Crad-Rin-Vah In reply to liamwhite1 [2015-03-22 22:37:04 +0000 UTC]
👍: 0 ⏩: 0
plushbrony101 In reply to PaulySentry [2015-03-22 23:10:08 +0000 UTC]
well, nice to see another nice comic. ^^
👍: 0 ⏩: 1
PaulySentry In reply to plushbrony101 [2015-03-22 23:25:28 +0000 UTC]
Thanks. Glad you like it. C:
👍: 0 ⏩: 1
plushbrony101 In reply to PaulySentry [2015-03-23 05:37:11 +0000 UTC]
may I ask you something?
👍: 0 ⏩: 1
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