HOME | DD

Published: 2013-12-11 02:21:43 +0000 UTC; Views: 1902; Favourites: 26; Downloads: 14
Redirect to original
Description
I happened to be sifting through ShadeFalcon's effects pack when I noticed this. Β Somehow, this effect was made transparent so that blending it to screen wouldn't be required. My question is... How is that possible, How is it done, and What programs are used to do it? If anyone knows how to do it, please tell me. Or, you could just tell me the technical term for it. I'd happily Google it and figure it out myself.Related content
Comments: 25
Kevitz In reply to Kevitz [2018-09-14 04:56:51 +0000 UTC]
My bad, I didn't read the description before commenting.
π: 0 β©: 0
OlManCrash [2016-10-15 11:18:06 +0000 UTC]
if you're looking at this in flash the way you do it is to make the effect into a movie clip and then set the blend to screen, lighten or add. doing it anywhere else idek but it would be something along the lines of that
π: 1 β©: 0
Shadow624 In reply to euamodeus [2014-01-24 04:58:02 +0000 UTC]
Uh... What? No. This is an attack special effect unique to Iku from Touhou: Scarlet Weather Rhapsody.
π: 0 β©: 1
euamodeus In reply to Shadow624 [2014-01-24 16:57:50 +0000 UTC]
Uh. Seriously? Wow. ' -'
Try to watch the Pikachu's final smash on SSBB =3
π: 0 β©: 1
Shadow624 In reply to euamodeus [2014-01-25 03:42:43 +0000 UTC]
Yeah I know what Volt Tackle looks like. It's infinitely more complicated looking than this.
π: 0 β©: 1
comicart1 [2014-01-05 21:37:56 +0000 UTC]
can you please help me out with a sprite animation im making one and im trying to make it like battlefield of prayers but it doesn't turn out rightΒ Β Β Β Β Β Β
π: 0 β©: 1
Shadow624 In reply to comicart1 [2014-01-06 03:36:11 +0000 UTC]
You're gonna have to be a lot more specific than that.
π: 0 β©: 1
comicart1 In reply to Shadow624 [2014-01-06 23:53:01 +0000 UTC]
im trying to animate it but it looks really bad everytime i animate it. it looks really choppy.
π: 0 β©: 1
Shadow624 In reply to comicart1 [2014-01-08 02:46:45 +0000 UTC]
That's something that takes practice and patience. It's not something I can really help with... :/
π: 0 β©: 0
RosalinaSama [2013-12-11 04:00:50 +0000 UTC]
I think you can get that by making something a png in photoshop and reducing the layer transparency, you'd have to use something to get rid of the black as well but i'm not sure what
π: 0 β©: 1
Shadow624 In reply to RosalinaSama [2013-12-11 04:25:19 +0000 UTC]
Yeah getting rid of the black is the whole problem. -_-'
π: 0 β©: 2
RosalinaSama In reply to Shadow624 [2013-12-11 15:33:06 +0000 UTC]
I tried looking for something that would do it in photoshop, but I found nothing... I thought it would just be as simple as one of the layer options like screen, blend or dissolve but it isn't damn
π: 0 β©: 0
CookiezEaterRu In reply to Shadow624 [2013-12-11 08:18:03 +0000 UTC]
Pff, so easy. Selective color. Learn how to use it, best thing ever.
ResultΒ i.imgur.com/h96o99H.png
π: 0 β©: 1
CookiezEaterRu In reply to CookiezEaterRu [2013-12-11 08:39:45 +0000 UTC]
Oh, thats not what you need, actually.
π: 0 β©: 1
CookiezEaterRu In reply to CookiezEaterRu [2013-12-11 08:51:26 +0000 UTC]
Photoshop > Select > Color range
Then select black color with an eyedropper tool, and play with different values, then ok and press delete button. Should work.
π: 0 β©: 1
CookiezEaterRu In reply to CookiezEaterRu [2013-12-11 09:30:14 +0000 UTC]
I just found better, but harder way. First of all change picture to CMYK colors. Then copy whole black channel and paste it as new layer to your RGB picture. may also work with white channel. Then invert this new layer. Use Color range tool again and select black color. Press ok, and then invert selection with right mouse click. Now just make black channel layer invisible, select your image layer and press delete.
Result - completely transparent black colorΒ i.imgur.com/OrLy69z.png
π: 0 β©: 1
Shadow624 In reply to CookiezEaterRu [2013-12-12 16:31:29 +0000 UTC]
Thanks a lot! But I got the result I wanted just be using the Color Range tool. It is useful indeed.
π: 0 β©: 0