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#lucyloudfanart #loudhousefanart
Published: 2018-12-09 15:25:37 +0000 UTC; Views: 2076; Favourites: 24; Downloads: 0
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Description
Get the Beatles Reference?Let me Know what you think in the comments below
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Comments: 29
TwilightSparkleJohn [2019-03-14 00:03:49 +0000 UTC]
Yes, I get the reference! I love that song, and the art style!
π: 0 β©: 1
TeagBrohman15 In reply to Flurr4 [2019-01-18 22:03:16 +0000 UTC]
Lucy: I donβt know...
π: 0 β©: 1
Flurr4 In reply to TeagBrohman15 [2019-01-18 22:11:46 +0000 UTC]
Me: "Oh, Ummm i don't think Lola will like you stealing her diamonds"
π: 0 β©: 0
gordonphilbin [2019-01-17 13:43:53 +0000 UTC]
Awesome Beatles/Loud House reference drawing!
π: 0 β©: 1
SillyOlBear1989 [2018-12-30 23:04:09 +0000 UTC]
Lucy Van Pelt: *in the next cloud over* I hear ya, sister.Β
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Simpsonsfanatic33 [2018-12-10 00:09:17 +0000 UTC]
Lol nice reference with Lucy Loud here
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AntiMatterChopsticks [2018-12-09 23:15:34 +0000 UTC]
Lucy: Why would I have diamonds when I have the purest isolation around me?
π: 0 β©: 1
TeagBrohman15 In reply to AntiMatterChopsticks [2018-12-09 23:17:00 +0000 UTC]
John Lennon: I donβt know
Ringo Starr: Me neither
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TeagBrohman15 In reply to MJEGameandComicFan89 [2018-12-09 20:47:13 +0000 UTC]
Good for you
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amir4z1z [2018-12-09 15:27:14 +0000 UTC]
Max: *Far away down* HEY LUCY! WHAT ARE YOU DOING UP THERE IN THE CLOUDS?!
π: 0 β©: 1
TeagBrohman15 In reply to amir4z1z [2018-12-09 15:31:40 +0000 UTC]
Lucy: thinking to myself
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amir4z1z In reply to TeagBrohman15 [2018-12-09 15:35:52 +0000 UTC]
Max: *He teleport to the clouds with lucy* Thinking to yourself?
π: 0 β©: 1
TeagBrohman15 In reply to amir4z1z [2018-12-09 15:37:02 +0000 UTC]
Lucy: Iβm Posing for an Album...
π: 0 β©: 1
amir4z1z In reply to TeagBrohman15 [2018-12-09 15:38:11 +0000 UTC]
Max: Hey lucy? I have a sharing for you.
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LivingOnLaughs In reply to TeagBrohman15 [2018-12-09 15:33:30 +0000 UTC]
That's a Beetles song reference, isn't it?
π: 0 β©: 2
MJEGameandComicFan89 In reply to LivingOnLaughs [2018-12-09 20:48:23 +0000 UTC]
It sure is!
π: 0 β©: 1