HOME | DD

#boxers #boxing #cute #female #sexy #foxyboxing #boxingirls
Published: 2018-06-03 09:46:02 +0000 UTC; Views: 4810; Favourites: 105; Downloads: 56
Redirect to original
Description
A new character based...or lifted right from, really, a friend of mine.I assume youre all familiar enough with Kyda, so I hope you can tell the difference
Now you just have to guess why shes called The Tooth Fairy!
Related content
Comments: 16
izzyartistic1 [2020-03-10 19:39:46 +0000 UTC]
You'll end up loosing teeth going up against her and she sure ain't paying you gir any teeth she knocks out of her opponent!Β
π: 0 β©: 0
EVBrock [2018-06-03 17:16:06 +0000 UTC]
She leaves a dollar under their head after she punches someone out?Β
π: 0 β©: 1
VeXeDZERO In reply to EVBrock [2018-06-18 19:18:02 +0000 UTC]
Heh. Hadn't thought about that yet lol
π: 0 β©: 0
Shanna1600 [2018-06-03 15:39:36 +0000 UTC]
It looks like the makings of a potential duo!!!!! Β
π: 0 β©: 1
VeXeDZERO In reply to Shanna1600 [2018-06-30 05:51:18 +0000 UTC]
I think so, Theres some funny stuff they can do together, thats for sure.
π: 0 β©: 0
VeXeDZERO In reply to Faeron-The-Wanderer [2018-06-30 05:51:00 +0000 UTC]
Most cool indeed
π: 0 β©: 0
BeanieTheBoxer In reply to Faeron-The-Wanderer [2018-06-03 12:49:55 +0000 UTC]
She looks great! I'm digging her!Β
π: 0 β©: 1
Erazer941 [2018-06-03 10:19:41 +0000 UTC]
hehe I like her.
She looks like she would fight in a higher weithclass than Kyda ( Hope she didnt get that wrong^^).
Still very fit great legs she must have some power.
Now to the guess mhhhh.
She will visit me when i lay some teeth under my pillow
And nah she looks to friendly and kind to be some crazy,Β vicious fighterΒ knocking out tooths
Β Β
btw: are those two dance or does Angela trying to inspect Kydas tooth with her left hand?
π: 0 β©: 1
VeXeDZERO In reply to Erazer941 [2018-06-30 05:50:40 +0000 UTC]
Kyda and Angela are friends! Kyda's gunna train her up
π: 0 β©: 0
fxboxing-fan [2018-06-03 10:16:52 +0000 UTC]
They were twins separated at birth!! I knew it!
π: 0 β©: 0