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JasonPoel β Math Proof
Published: 2007-07-29 01:14:58 +0000 UTC; Views: 16274; Favourites: 138; Downloads: 349
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2 multiplied by 0 is the same as 1 multiplied by 0. The only way to divide by 0, is if the numerator itself is 0. Considering the only number this equation may apply to is 0, A=0 and B=0. 2B=B. 2x0 = 0. 0 = 0.
Proven mathematically, and still correct thank you and good day.
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A=B,That means A-B=0,you can't make it aΒ denominator at step 4.
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everyone makes mistakes at the division steps lol
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you know, this whole thing started out with two unknown numbers, so couldn't they have started as a=1 and b=2? and they just kept tat logic and made a complex way of salving the equation back to its original answer?
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Is this algebra 2? I'm not on that, but it seems easy...
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Oh.Β Indeterminant forms?Β NO PROBLEM.Β Let's just take some limits and use some l'Hopital's Rule and and and and.....
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I tried to read the comments below but most of it is correcting something. Β
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Given A = B
A^2 = A*B
Proof
A^2 - B^2 = A*B - B^2
A^2 = A*B -B^2 +B^2
A^2 = A*B + 0
A^2 / A = A*B / A
A = B
(A^2 - B^2) / A-B =/= A - B
It's a common mistake but it just doesn't work that way. Your thinkng
(A - B)^2 / A-B = A-B
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I'm doing college algebra and omg I hate it SOOO much 
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it is difficult to infer the equation 'A+B =B' Β . . .
how can deduce equation 'A+B = B' by A^2-B = AB-B^2 with 'A-B' 'A-B' . . . ?
I can't find the relation between 'A-B' and 'A+B = B' . . . Though I approach this wit Mathmatical logicl . . Β
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Is it bad that I understand this... ?
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this is an easy one, the answer is : NOBODY CARES!
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Your proof here is incorrect: most notably, you divide by zero, which invalidates the entire mathematical operation. You can never do that - your answer would be, if followed correctly, "undefined=undefined," a factual statement.
Dividing by variables equal to 0 can get you all sorts of weird shit that's factually incorrect, because you can't do that. I'm a calculus student and our teacher handed out a shitload of 0s on the examination this time around because people kept doing just that on a problem, which lead them to incorrectly finding an integral. The step of division here would only work of A=/=B.
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A-B is zero.You cannot divide by zero.
So that was....AN ILLEGAL OPERATION
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OH MY GOSH YOU DIVIDED BY ZERO YOU'VE KILLED US ALL.
... I know a simpler (kinda maybe sorta) version.
A=1 B=1
A=B
A^2=A*B
A^2-B^2=A*B-B^2
(A+B)(A-B)=B(A-B)
A+B=B
1+1=1
2=1
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once again, you are diving by zero... as you divide both sides by (A-B) to get from
(A+B)(A-B)=B(A-B)
to
A+B=B
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wow..i read the "proof"...you'll get a zero for dat dude....XDDDDDDDDDDDDDDDDDDDDDD.....I HAD A MATH TEST TODAY AND I SUCKED
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2nd step, already wrong, it should be A2=A+B
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Doesn't work. You can't divide by zero. But it's a good concept anyway.
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A=B.
A-B=0.
In a later step, you have to divide by (A-B). That's dividing by zero; there's no solution.
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Ayup. That pretty much explains it. There's a similar 'proof' with a similar fallacy that 'proves' that -1=1.
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WRONG! Using calculus, you can calculate the limit of the fraction, when A--->B, which allows you to cancel, on the numerator, the A-B part, on both sides of the equation. This simply proves that A is different than B, as you can't have 2 = 1, which is a powerful tool in advanced geometry and calculus.
-A physicist
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I used an incorrect example; the -1=1 proof takes advantage of the ambiguity provided by the square-root operator (which occurs because 'squaring' isn't a one-to-one function). It actually doesn't have much to do with dividing by zero.
By the way, your example would work... if A were a function and B a particular evaluation of that function. Here, I suspect, A and B are constants, which causes your argument to fall apart because the derivative of constants is always zero. In conventional arithmetic, dividing by zero is not allowed because it causes algebra to lose its functionality and requires a solution to the equation:
X/(infinity)=0
Specifically:
X = (infinity) * 0
Where X is a constant.
And, Mr. Physicist-Pants, 'I' am a mathematician. So there. 
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Wow.
I never knew people get get so worked up over a math problem because they actually went through it.
Congrats to you people who can do this.
Mazel tav and all that happy crap.
It's an expressive work.
Get over it.
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HOW did A=B go to A+B=B??
This "proof" is wrong
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Cute, but line 5 is incorrect, because line 4 assumes that A-B is not equal to zero. Also
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no, it all equals 0, bause the step where you went wrong (A^2-B^2) would equal 0!!!!
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what?! what...how...how'd ya do that???
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if a equals b... then a-b equals 0... and you can't divide by 0... UNDEFINEHDUH!!!
my brain...
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the formula works... but the person doing the math was wrong lol.
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Rofl this proof is funny because it makes people so angry.
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thats still half a proof though XD it didnt put any theorms ;3 <- me
still funny!
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I think what's wrong is that A is supposed to be substituted by B (or vise versa) and you're leaving what you were substituting in the equation. However, this is just a theory. The math, otherwise, is correct.
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No, not really.
A2 - B2 = (A-B)(A+B) = 0; it's a common formula.
A2 = A2 , ergo:
A2 - A2 = (A-A)(A+A) = 0 x 2A = 0
Voila. Just to point out one mistake. The others I'll leave be, since they're glaringly obvious.
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oh, and in the first line =0 because A = B; the formula does not equal to 0 itself.
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