HOME | DD

#lee #cardcaptor #cardcaptors #cardcaptorsakura #characterdesign #conceptart
Published: 2016-01-05 11:17:45 +0000 UTC; Views: 1576; Favourites: 35; Downloads: 0
Redirect to original
Description
Work for my Final Masters Project - Cardcaptors: Quest for the ClowRelated content
Comments: 13
Evilgidgit [2016-01-05 17:11:42 +0000 UTC]
The closest to the original design, but very fitting.
π: 0 β©: 1
JoshuaDunlop In reply to Evilgidgit [2016-01-05 21:45:45 +0000 UTC]
Glad you like it Lee was going to be black at first, but it didnt work. So I went back to the more traditional design
π: 0 β©: 1
Makosharkman In reply to JoshuaDunlop [2017-09-19 22:12:26 +0000 UTC]
Very well drawn.Β
He reminds me of a boy from a book I am writing.
π: 0 β©: 1
Makosharkman In reply to JoshuaDunlop [2017-09-24 18:02:43 +0000 UTC]
your welcome.
also out of curiosity do you take request?
π: 0 β©: 1
JoshuaDunlop In reply to Makosharkman [2017-09-25 11:46:06 +0000 UTC]
Not requests ImΒ afraid, only commisions
π: 0 β©: 1
Makosharkman In reply to JoshuaDunlop [2017-09-25 12:12:55 +0000 UTC]
do you take points or pay pal?
also what style is Lee hair in is it shaggy?
π: 0 β©: 1
JoshuaDunlop In reply to Makosharkman [2017-09-25 15:55:26 +0000 UTC]
Paypal yer I'd say its shaggy
π: 0 β©: 1
Makosharkman In reply to JoshuaDunlop [2017-09-27 12:27:38 +0000 UTC]
how much?
I see and Lee reminds me of a boy from a book I am writing which is who I wanted you to draw?.
π: 0 β©: 1
JoshuaDunlop In reply to Makosharkman [2017-09-28 12:00:55 +0000 UTC]
Do you just want a shot of the boy like Lee? What kind of budget do you have?
π: 0 β©: 1
Makosharkman In reply to JoshuaDunlop [2017-09-29 03:32:41 +0000 UTC]
for now yes just draw him until I now how much it will cost like how much does it cost?
anyway I will send you a note about the boy story.
π: 0 β©: 1
JoshuaDunlop In reply to Makosharkman [2017-09-29 16:07:53 +0000 UTC]
Well my 3D work is Β£375 a day, but for 2D like Lee I'd be happy to drop it down to like Β£100 a day. probably only take a day, 2 max depending on the design
π: 0 β©: 1