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Vladimir-Bulatov — Self similar 'Circle limit I' by-nc-sa

Published: 2012-02-23 07:20:47 +0000 UTC; Views: 3698; Favourites: 30; Downloads: 197
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Description M.C.Escher "Circle Limit I" getting smaller and smaller..
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Comments: 11

timemit [2014-08-05 13:20:17 +0000 UTC]

fantastic

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marecaca [2012-03-20 12:48:35 +0000 UTC]

WOW! beautifull!

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Vladimir-Bulatov In reply to marecaca [2012-03-25 05:39:21 +0000 UTC]

Thank you!

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cyberxaos [2012-02-23 13:56:12 +0000 UTC]

Gorgeous, as usual!

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Vladimir-Bulatov In reply to cyberxaos [2012-02-24 17:30:40 +0000 UTC]

Thank you!

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cyberxaos In reply to Vladimir-Bulatov [2012-02-24 19:13:56 +0000 UTC]

You're very welcome!

More! More! More!

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dark-beam [2012-02-23 08:26:25 +0000 UTC]

Omg, crazy

I really would like to see a piece of your code.

I write formulas too, and I would love to implement some of your concepts, especially the "normal" circlelimit. I only found partial implementations on the internet. I assume you use a single iterative formula (not a big memory stack) else I can't use it

Luca

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Vladimir-Bulatov In reply to dark-beam [2012-02-24 17:44:33 +0000 UTC]

I think few people ([link] ) implemented some hyperbolic tilings in a Apophysis
and Mandelbul3D.
I not quite know yet how these programs work to be able to provide
formulas. It all are Moebius transformations.

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dark-beam In reply to Vladimir-Bulatov [2012-02-24 23:40:30 +0000 UTC]

I did an apollonian fractal, it is the same? Or needs a log()? thks

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Vladimir-Bulatov In reply to dark-beam [2012-02-25 02:42:03 +0000 UTC]

Apollonian gasket is made by reflections in 3 circles, which touch each other.
Hyperbolic triangle tilings are made by reflections in 3 circles with intersection angles pi/k, pi/m, pi/n.
This image is generated by reflections in 5 circles.
4 circles make a chain with intersection angles pi/2,pi/2, pi/2 pi/3. The angles of intersection of 5th circle with other four are pi/2,pi/2,pi/2,pi/4.
In addition a conformal mapping (cirlce to a band) is applied to stretch two selected limit points to +-oo and exponential mapping is applied to wrap image into a spiral.
The idea of bended quadrilateral hyperbolic kaleidoscope is described at my site http:/bulatov.org/math/1107
The fifth circle (hyperbolic plane) adds nice fractal twist.

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dark-beam In reply to Vladimir-Bulatov [2012-02-25 10:13:05 +0000 UTC]

Striking thanks! I am not understanding much but thanks

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